What size service is generally required for a 120 V 240 V single phase load with a demand factor of 36 KVA?

Study for the Rhode Island Electrical License Test. Engage with flashcards and multiple choice questions, each equipped with hints and explanations. Prepare effectively for your exam!

To calculate the size of the service required for a 120/240 V single-phase load with a demand factor of 36 KVA, it's important to understand the relationship between amperage, voltage, and kilovolt-amperes (KVA).

First, we can use the formula for converting KVA to amperes in a single-phase system:

I (in Amperes) = (KVA × 1000) / V

Where:

  • KVA is the total demand in kilovolt-amperes (in this case, 36 KVA)

  • V is the voltage (in this case, 240 V)

Substituting the values into the formula gives:

I = (36 KVA × 1000) / 240 V

I = 36000 / 240

I = 150 Amperes

This calculation shows that a service of 150 Amperes is necessary to safely handle the load demand of 36 KVA. This service size must also account for any additional factors such as future growth, which is why it's a standard practice to select a breaker or service size that is larger than the calculated demand.

In the context of the provided options, 150 Amperes

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